Write a program that reads in a number n. Then it should write out all the powers of number 10 that are smaller than the number n.

#include <iostream>

using namespace std;

int main()

{

    double product = 1; // otherwise it'll all be 0

    double n;

    double sum;

    cout << "Enter a number:\t";

    cin >> n;

    while (product <= n)

        product *= 10;

        for (double i = 0; i < n; i++)

        {

            product*10;

        }

        cout << n << " is smaller than the number " << product << endl;

            do {

                product *= 10;

                cout << "So is: " << product << endl;

            } while (product < 1000);

    return 0;

}